[tex]\begin{gathered} \frac{(x^4)^2\text{ x}^{\text{ -3}}}{x^5x^9}\text{ =} \\ When\text{ the exponents are together separeted by a parenthesis, the property says we have to multiply them} \\ \frac{x^{4\text{ x 2}}x^{\text{ -3}}}{x^5x^9}= \\ When\text{the number with exponents are multiplying, then the property says we have to add them together} \\ \frac{x^8x^{\text{ -3}}}{x^5x^9}= \\ \\ \frac{x^{8\text{ + \lparen-3\rparen}}\text{ }}{x^{^5}x^9}= \\ \\ \frac{x^5}{x^5x^9}=\text{ } \\ \\ Here,\text{ we can eliminate the repeated number in both numerator and denominator which is x}^5 \\ \frac{1}{x^9}\text{ that's the final answer} \end{gathered}[/tex]
