1. Consider NH3.If it dissolves in water(i) NH3 + H20 + NHẤ4+ H2O(ii)NH3 + H2O → NH+3 + OH-(iii) NH3 + H2O + NH+4+ OH-(iv) NH3 + H2O → NH+4+ OH-Which represents the dissolution of NH3 in water(a) i(b) ii (c) iii (d) iv (e) iii and iv2. HOA2+H20 . → H3O+ + OA-CIn this reaction:(i) OA c is the conjugate base of H2O(ii)OA-c is the conjugate base of HOAc (iii) H3O+ is theсconjugate base of HOA.(iv) H3O+ is the conjugate acid of H2O(a) i(b) ii (c) iii (d) iv (e) none3. Arrange the following according to increasing acid strength(i) Ka= 2.5 + 10-15(ii) Ka= 9.0 + 10-9(iii) pKa= 7.5(iv) % dissociation =100(a) iv, iii, ii, i2(b) ii, I, iii, iv(c) i, iii, iv, ii(d) i, ii, iii, iv(e) iii, iv, ii, i2



Answer :

1. Ammonia is a colorless gas with a chemical formula of NH3, when it comes in contact with water, it will be transformed into Ammonium ion and it will produce one hydroxide ion, and this is why Ammonia will present a more basic (pH) behavior, the reaction that represents this behavior is:

NH3 + H2O -> NH4+ + OH-

Number 4 is the only one that represents it well

Number 3 has the same reaction but since there is a plus sign instead of an arrow, I consider it wrong.