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1. A gas with a volume of 4.0 L at a pressure of 2 08 atm is allowed to expand to a volume of 12.0 L. What is the pressure in atm in the container if the temperature remains constant. Please show work (including the equation you used). --------- 2. The volume of a gas is 200 mL at 350.0 kPa pressure. What will the volume be when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant. Please show all work for full credit. Please show work (including the equation you used).



Answer :

Explanation

To solve this, we consider Boyle's Law:

It relates gas pressure to volume while keeping other parameters such as temperature and amount of substance constant.

Equation we use here is p1 x V1 = p2 x V2 (1)

(p for pressure and V for volume)

p1 = 2.08 atm

V1 = 4.0 L

If the gas expands, the pressure will be lower than 2.08 atm.

p2 = unknown

V2 = 12.0 L

From (1) we clear p2:

=> p1 x V1/V2 = p2

=> 2.08 atm x 4.0 L/12.0 L = p2

=>0.69 atm = p2

Answer: p2 = 0.69 atm

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