The given equation is expressed as
x + 3y = 6
To determine wether the ordered pairs are solutions of the equation, we would substitute the values of x and y in the ordered pairs into the equation. If both sides of the equation are equal, then the ordered pair is a solution. We have
a) For a = 3 and y = 1, we have
3 + 3(1) = 6
3 + 3 = 6
6 = 6
It is a solution
b) For x = 6 and y = 0
6 + 3(0) = 6
6 + 0 = 6
6 = 6
It is a solution
c) - 2 + 3(2/3) = 6
- 2 + 2 = 6
0 is not equal to 6
It is not a solution
The correct answers are options a and b
