[tex]\frac{8^{12}}{4^3}[/tex]
1. Rewrite the expression to get the numerator and denominator with the same base:
[tex]\frac{(2^3)^{12}}{(2^2)^3}=\frac{2^{36}}{2^6}[/tex]
2. Divide by leavinfg the same base and subtracting the exponents:
[tex]\frac{2^{36}}{2^6}=2^{36-6}=2^{30}[/tex]
Write the result with base 4:
[tex]2^{30}=(2^2)^{30/2}=4^{15}[/tex]As you can see above any of the given expression is equivalent to the given expression.Answer: none of these
