So,
We want to find the value in the box such that:
[tex]\frac{(\frac{2+x}{6}+1)}{4}=\frac{3}{8}[/tex]
I wrote x instead the box.
To solve this equation, the first thing we need to do is to let the "x term" alone.
For this, we could start by multiplying both sides of the equation by 4:
[tex]\frac{2+x}{6}+1=\frac{12}{8}[/tex]
Now, we could substract 1 to both sides:
[tex]\begin{gathered} \frac{2+x}{6}=\frac{12}{8}-1 \\ \\ \frac{2+x}{6}=\frac{4}{8} \end{gathered}[/tex]
And then multiply by 6:
[tex]2+x=\frac{24}{8}[/tex]
Now, substract 2:
[tex]\begin{gathered} x=\frac{24}{8}-2 \\ \\ x=3-2 \\ x=1 \end{gathered}[/tex]
Therefore, the value in the box should be 1.
