Answer:
[tex]C[/tex]
Explanation:
Here, we want to calculate the percentage composition of the compound formed when oxygen reacts with iron
We have the equation of reaction as follows:
[tex]4Fe_{(s)}\text{ + }3O_{2(g)}\text{ }\rightarrow\text{ }2Fe_2O_{3(s)}[/tex]
The compound formed is Fe2O3
Now, let us get its percentage composition
The molar mass of the compound is 160 g/mol
The atomic mass of iron is 56 amu
The atomic mass of oxygen is 16 amu
Now, let us get the percentage composition:
[tex]\begin{gathered} \text{Iron = }\frac{2\times56}{160}\text{ }\times\text{ 100 \% = }70\text{ \%} \\ \\ \text{Oxygen = }\frac{3\times16}{160}\text{ = 30\% } \end{gathered}[/tex]
The closest here is thus the option C
