Answer :
Answer:
[tex]\begin{equation*} C_{18}H_{27}NO_3 \end{equation*}[/tex]Explanations:
Given the following mass of the elements
Mass of Carbon = 9.72 grams
Mass of Hydrogen = 1.225grams
Mass of nitrogen = 0.631 grams
Mass of oxygen = 13.736 - (9.72+1.225+0.631)
Mass of oxygen = 13.736 - 11.576 = 2.16grams
Convert the mass to moles
Moles of Carbon = 9.72/12 = 0.81moles
Moles of Hydrogen = 1.225/1 = 1.225moles
Moles of Nitrogen = 0.631/14 = 0.0451moles
Moles of Oxygen = 2.16/16 = 0.135moles
Divide by the lowest moles
For Carbon = 0.81/0.0451 = 17.96 = 18
For Hydrogen: 1.225/0.0451 = 27.16 = 27
For Nitrogen: 0.0451/0.0451 = 1
For Oxygen: 0.135/0.0451 = 3
Determine the empirical formula
[tex]Empirical\text{ }formula=C_{18}H_{27}NO_3[/tex]Determine the molecular formula
[tex]\begin{gathered} (C_{18}H_{27}NO_3)n=305.4 \\ (18(12)+27(1)+14+3(16))n=305.4 \\ (216+27+14+48)n=305.4 \\ 305n=305.4 \\ n=\frac{305.4}{305} \\ n\approx1 \\ (C_{18}H_{27}NO_3)_1=C_{18}H_{27}NO_3 \end{gathered}[/tex]Hence the molecular formula for capsacin is C18H27NO3
