The first step to apply using the elimination method is by multiplying the whole value of equation 1 by 3/2.
[tex]\begin{gathered} (2x+3y=5\text{ )}\times\frac{3}{2} \\ -3x+2y=-14 \\ 3x+\frac{9}{2}y=\frac{15}{2} \\ -3x+2y=-14 \\ \frac{9}{2}y+2y=\frac{15}{2}-14 \\ \frac{9y+4y}{2}=\frac{15-28}{2} \\ \frac{13y}{2}=\frac{-13}{2} \\ 26y=-26 \\ y=-1 \\ -3x+2(-1)=-14 \\ -3x-2=-14 \\ -3x=-14+2 \\ -3x=-12 \\ x=\frac{-12}{-3} \\ x=4 \end{gathered}[/tex]
