x=2
Explanation
we have 2 triangles (45-45-90 degrees)
for triangle 1
[tex]\begin{gathered} \text{side}=y \\ \text{hypotenuse}=4 \\ \text{then} \\ 4=y\sqrt[]{2} \\ \frac{4}{\sqrt[]{2}}=y=\frac{2\sqrt[]{2}\sqrt[]{2}}{\sqrt[]{2}}=2\sqrt[]{2} \end{gathered}[/tex]
now, for triangle 2
side=x
hypotenuse = y
then
[tex]\begin{gathered} \text{hypotenuse}=y=2\sqrt[]{2} \\ \text{the side} \\ \text{hypotenuse}=x\sqrt[]{2} \\ \text{Hence} \\ 2\sqrt[]{2}=x\sqrt[]{2} \\ x=2 \end{gathered}[/tex]
I hope this helps you
