Given: The below
[tex]\begin{gathered} ME(Margin-of-error)=1.6\% \\ proportion(p)=34\% \end{gathered}[/tex]To Determine: The conclusion about p using an absolute value inequality
Solution
Using the absolute inequality about p using an absolute value inequality below
[tex]|p-\hat{p}|\leq ME[/tex]Substituting the given
[tex]\begin{gathered} p-E\leq p\leq p+E \\ 34\%-1.6\%\leq p\leq34\%+1.6\% \\ 32.4\%\leq p\leq35.6\% \end{gathered}[/tex]Hence, p is most likely going to be between 32.4% and 35.6%
(32.4% ≤ p ≤ 35.6%)