The given expression is:
[tex]3(x+y)+2x^2+(1+y)^2[/tex]We have to evaluate the expression for x = 4 and y =1. For that, just put the values of x and y in the expression.
[tex]3(4+1)+2(4)^2+(1+1)^2[/tex][tex]3(5)+2(16)^{}+(2)^2[/tex][tex]15+32^{}+4[/tex]
=> 51
Hence, the answer is 51.