In the given problem,
[tex]\begin{gathered} \Delta GHJ\approx\Delta PQR \\ \frac{GH}{PQ}=\frac{HJ}{QR}=\frac{GJ}{PR} \\ \angle G=\angle P \\ \angle H=\angle Q \\ \angle J=\angle R \end{gathered}[/tex]Thus value of tanG, sinG and cosG can be determined as,
[tex]\begin{gathered} \tan G=\tan P=\frac{QR}{PR}=\frac{15}{8} \\ \sin G=\sin P=\frac{QR}{QP}=\frac{15}{17} \\ \cos G=\cos P=\frac{PR}{QP}=\frac{8}{17} \end{gathered}[/tex]Thus, the above expression gives the requried value of tanG, sinG and cosG.