Given angles are alternate exteior angles: pair of angles on the outer side of each of parallel lines but opposite sides of the transversal.
When two lines being crossed are parallel line the alternate exterior angles are equal:
[tex]5x-5=6x-27[/tex]
Use the equation above to find the value of x:
[tex]\begin{gathered} 5x-5x-5=6x-5x-27 \\ -5=x-27 \\ -5+27=x-27+27 \\ 22=x \\ \\ x=22 \end{gathered}[/tex]
Then, the value of x is 22
