1. No Slope
2. -4/3
3. 4/3
4. No Slope
1) Let's start by calculating the slope of each segment:
1) Vertical lines do not have a slope, since the slope is the steepness of a line.
So m is undefined
2) Picking points (-8,8) and (-5,4) and plugging into the slope formula:
[tex]m=\frac{4-8}{-5+8}=\frac{-4}{3}=-\frac{4}{3}[/tex]
3) For this line segment (3) let's pick and plug points (-5, 4) and (-2,8)
[tex]m_3=\frac{y_2-y_1}{x_2-x_1}\Rightarrow m=\frac{8-4}{-2+5}=\frac{4}{3}[/tex]
4) Since we have another vertical line then, the slope it's undefined because of that (considering points (-2,8) and (-2,1)
[tex]m=\frac{8-1}{-2+2}=\frac{7}{0}=\text{undefined!}[/tex]
Hence, there is no slope
4) Hence, for Quadrant II (letter M) we have:
1. No Slope
2. -4/3
3. 4/3
4. No Slope
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