Solution:
Give the sequence:
[tex]0,\text{ 100, 200, 300,..}[/tex]The common difference is the difference between two consecutive terms.
Thus, the common diffrence is evaluated as
[tex]\begin{gathered} 100-0 \\ =100 \end{gathered}[/tex]Thus, from the explicit formula,
[tex]\begin{gathered} a_n=a+(n-1)d \\ where \\ a=0 \\ d=100 \end{gathered}[/tex]The explicit form is evaluated to be
[tex]\begin{gathered} a_n=0+(n-1)100 \\ \implies\text{A}_n=-100+100n \end{gathered}[/tex]The recursive form is evaluated as
[tex][/tex]