A farm has 5 brown cows and 10 white cows
Total of cows:
[tex]5+10=15[/tex]Probability is represented by:
[tex]P=\frac{NU\text{MBER OF FAVOURABLE OUTCOMES}}{\text{TOTAL NUMBER OF FAVOURABLE OUTCOMES}}[/tex]So, the probability of a brown cow escapes:
[tex]\begin{gathered} P=\frac{5}{15}=0.33\text{ (decimal form)} \\ P=0.33\cdot100=33\text{ percent} \end{gathered}[/tex]