Given the right triangle:
The angles ∡A and ∡B are complementary, then:
[tex]\begin{gathered} \measuredangle A=90\degree^{}-\measuredangle B \\ \measuredangle A=90\degree^{}-33.7\degree \\ \measuredangle A=56.3\degree \end{gathered}[/tex]Now, using the trigonometric functions:
[tex]\begin{gathered} \sin A=\frac{a}{c} \\ \sin B=\frac{b}{c} \end{gathered}[/tex]Then, using the values of A, B, and c to find a and b:
[tex]\begin{gathered} \sin 56.3\degree=\frac{a}{2.2}\Rightarrow a=1.8\text{ mm} \\ \sin 33.7\degree=\frac{b}{2.2}\Rightarrow b=1.2\text{ mm} \end{gathered}[/tex]