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Please help with this problem:Solve for b.16 = a^2 + b^2A. b = 16 − a2B. b = ±16−a^2−−−−−−√C. b = ±16+a^2−−−−−−√D. b = 4−a

Please help with this problemSolve for b16 a2 b2A b 16 a2B b 16a2C b 16a2D b 4a class=


Answer :

SOLUTION

We want to solve for b in the equation

[tex]16=a^2+b^2[/tex]

Solving we have

[tex]\begin{gathered} 16=a^2+b^2 \\ we\text{ will move a}^2\text{ to meet 16, we have } \\ 16-a^2=b^2 \\ b^2=16-a^2 \\ move\text{ the square to the other side, it becomes square root, we have } \\ b=\pm\sqrt{16-a^2} \end{gathered}[/tex]

Hence the answer is the second option