Solution
We have the following points given:
(x1 =10, y1= -28) (x2= 4, y2=-4)
We can find the slope of the line like this:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-4-28}{4-10}=\frac{32}{6}=\frac{16}{3}[/tex]And the intercept can be founded on this way:
[tex]-4=\frac{16}{3}(4)+b[/tex]Solving for b we got:
[tex]b=-\frac{64}{3}-4=-\frac{76}{3}[/tex]Then the equation would be:
[tex]y=\frac{16}{3}x-\frac{76}{3}[/tex]