Given:-
[tex]x^2-6x+8=0[/tex]
To find the simplified form and the mistake.
So now we use the formula,
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
So now we substitute the value. so we get,
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{6\pm\sqrt[]{6^2-4\times1\times8}}{2\times1} \\ x=\frac{6\pm\sqrt[]{36-32}}{2\times1} \\ x=\frac{6\pm\sqrt[]{4}}{2\times1} \\ x=\frac{6\pm2}{2} \end{gathered}[/tex]
So now we get,
[tex]\begin{gathered} x=\frac{6\pm2}{2} \\ x=\frac{6+2}{2},x=\frac{6-2}{2} \\ x=\frac{8}{2},x=\frac{4}{2} \\ x=4.x=2 \end{gathered}[/tex]
So the value of x is,
[tex]4,2[/tex]
So the mistake is in step 5.
