Given:
Two pentagons are similar.
[tex]\begin{gathered} CD=6 \\ CB=2 \\ BA=3 \\ RQ=1.6 \\ QP=2.4 \\ RS=x \end{gathered}[/tex]
Required:
To find the value of x.
Explanation:
Write proposition,
[tex]\frac{CD}{x}=\frac{CB}{RQ}[/tex]
Substitute the given values, we get
[tex]\begin{gathered} \frac{6}{x}=\frac{2}{1.6} \\ 2x=6\times1.6 \\ 2x=9.6 \\ x=4.8 \end{gathered}[/tex]
Final Answer:
The value of x is,
[tex]x=4.8[/tex]
