6.5Joules
The formula for calculating the amount of heat that must be added is expressed as:
[tex]Q=mc\triangle t[/tex]where:
• m is the ,mass ,of the object
,• c is the s,pecific heat capacity
,• △t is the ,change in temperature
Given the following parameters
m = 10grams
c = 0.13 J/g C
△t = 5 C
Substitute the given parameters into the formula
[tex]\begin{gathered} Q=10\cancel{g}\times\frac{0.13J}{\cancel{g}^\cancel{^0C}}\times5\cancel{^0C}^ \\ Q=10\times0.13J\times5 \\ Q=1.3\times5 \\ Q=6.5Joules \end{gathered}[/tex]This shows that 6.5Joules of heat must be added to a 10 gram sample of Gold to increase its temperature by 5 C.