Adults who are being tested for dementia are asked to perform mental tasks such as listing as many animals as they can in one minute. Here are the numbersof animals listed in one minute by 10 adults. 11, 13, 22, 14, 24, 17, 20, 21, 23, 17Send data to calculator(a) What is tinteger, round yof this data set? If your answer is not answer to one decimal place.(b) What is the median of this data set? If your answer is notan integer, round your answer to one decimal place.(c) How many modes does the data set have, and what aretheir values? Indicate the number of modes by clicking in theappropriate circle, and then indicate the value(s) of themode(s), applicable.00zero modesone mode:two modes: andG

Question

Answered

Answer :

MorgenB216426 MorgenB216426 · Answer 1 · 2022-10-31T00:10:33-04:00

Given

Number of animals listed in one minute by 10 normal adults.

11, 13, 22, 14, 24, 17, 20, 21, 23, 17

Find

a) Mean

b) Median

c) Mode

Explanation

mean is given by sum of observations divided by number of observations.

so , mean =

[tex]\begin{gathered} mean=\frac{11+13+22+14+24+17+20+21+23+17}{10} \\ \\ mean=\frac{182}{10}=18.2 \end{gathered}[/tex]

to find median , we need to arrange data in ascending order.

so ,

11 , 13 , 14 , 17 , 17 , 20 , 21 , 22 , 23 , 24

number of data is 10 which is an even number .

so ,

,median =

[tex]\begin{gathered} \frac{n}{2},\frac{n}{2}+1 \\ \\ \frac{10}{2},\frac{10}{2}+1 \\ \\ 5th,6th \end{gathered}[/tex]

median =

[tex]\begin{gathered} \frac{5th+6th}{2} \\ \\ \frac{17+20}{2} \\ \\ \frac{37}{2} \\ \\ 18.5 \end{gathered}[/tex]

mode = 17 because it occurs maximum times in data set.

Final Answer

Hence ,

mean = 18.2

median = 18.5

mode = 17