Answer :

Answer:

10.  A translation of 4 units down.

11.  A translation of 6 units left.

12.  A reflection in the y-axis, followed by a vertical compression by a factor of ¹/₂.

13.  A horizontal compression by a factor of ¹/₅, followed by a reflection in the x-axis.

14.  A translation of 4 units left, followed by a vertical stretch by a factor of 3, followed by a translation of 6 units down.

15.  A horizontal compression by a factor of ²/₃, followed by a reflection in the x-axis, followed by a translation of 5 units down.

Step-by-step explanation:

Transformations

[tex]\textsf{For $a > 0$}:[/tex]

[tex]f(x+a) \implies f(x) \: \textsf{translated $a$ units left}.[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated $a$ units right}.[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated $a$ units up}.[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated $a$ units down}.[/tex]

[tex]a\:f(x) \implies f(x) \: \textsf{stretched parallel to the $y$-axis (vertically) by a factor of $a$}.[/tex]

[tex]f(ax) \implies f(x) \: \textsf{stretched parallel to the $x$-axis (horizontally) by a factor of $\dfrac{1}{a}$}.[/tex]

[tex]-f(x) \implies f(x) \: \textsf{reflected in the $x$-axis}.[/tex]

[tex]f(-x) \implies f(x) \: \textsf{reflected in the $y$-axis}.[/tex]

Question 10

[tex]\textsf{Given}: \quad g(x)=f(x)-4[/tex]

Therefore, the transformation to get from f(x) to g(x) is:

  • Translation of 4 units down.

Question 11

[tex]\textsf{Given}: \quad g(x)=f(x+6)[/tex]

Therefore, the transformation to get from f(x) to g(x) is:

  • Translation of 6 units left.

Question 12

[tex]\textsf{Given}: \quad g(x)=\dfrac{1}{2}f(-x)[/tex]

Therefore, the series of transformations to get from f(x) to g(x) is:

  • Reflection in the y-axis.
  • Vertical compression by a factor of ¹/₂.

Question 13

[tex]\textsf{Given}: \quad g(x)=-f(5x)[/tex]

Therefore, the series of transformations to get from f(x) to g(x) is:

  • Horizontal compression by a factor of ¹/₅.
  • Reflection in the x-axis.

Question 14

[tex]\textsf{Given}: \quad g(x)=3f(x+4)-6[/tex]

Therefore, the series of transformations to get from f(x) to g(x) is:

  • Translation of 4 units left.
  • Vertical stretch by a factor of 3.
  • Translation of 6 units down.

Question 15

[tex]\textsf{Given}: \quad g(x)=-f\left(\dfrac{3}{2}x\right)-5[/tex]

Therefore, the series of transformations to get from f(x) to g(x) is:

  • Horizontal compression by a factor of ²/₃.
  • Reflection in the x-axis.
  • Translation of 5 units down.