Answer :

we have the following:

[tex]\begin{gathered} A=P\cdot(1+r\cdot t) \\ r=\frac{R}{100}=\frac{6}{100}=0.06\text{ per year} \\ A=530\cdot(1+0.06\cdot1) \\ A=530\cdot1.06 \\ A=\text{ }561.8 \end{gathered}[/tex]

The answer is 561.8$

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