Solution:
The general equation of a line in slope-intercept form is given below as
[tex]y=mx+c[/tex]
The equation of the line given is
[tex]x+4y=8[/tex]
Concept:
We will make y the subject of the formula
[tex]\begin{gathered} x+4y=8 \\ 4y+x-x=8-x \\ substract\text{ x from both sides} \\ 4y+x-x=8-x \\ 4y=8-x \\ divide\text{ bpoth sides by 4} \\ \frac{4y}{4}=-\frac{x}{4}+8 \\ y=-\frac{1}{4}x+2 \end{gathered}[/tex]
Hence,
The equation of the line in slope-intercept form is
[tex]\Rightarrow y=-\frac{1}{4}x+2[/tex]
