we have the equation
[tex]3^{(x-1)}=2[/tex]Solve for x
Apply log on both sides
[tex]\log 3^{(x-1)}=\log 2[/tex]Applying property of log
[tex]\begin{gathered} (x-1)\cdot\log 3^{}=\log 2 \\ x-1=\frac{\log 2}{\log 3} \\ \\ x=\frac{\log2}{\log3}+1 \end{gathered}[/tex]therefore
the answer is
[tex]x=\frac{\log2}{\log3}+1[/tex]