33. Option A is correct
In order to get the measure of side BC, we need to determine the measure of first as shown:
[tex]\begin{gathered} \angle A+\angle B+\angle C=180^0 \\ 93+\angle B+58=180 \\ \angle B=180-(93+58) \\ \angle B=180-151 \\ \angle B=29^0 \\ \end{gathered}[/tex]Next is to determine the measure of BC using the sine rule as shown:
[tex]\begin{gathered} \frac{BC}{sin\angle A}=\frac{AC}{sin\angle B} \\ \frac{BC}{sin93}=\frac{16}{sin29} \end{gathered}[/tex]Cross multiply
[tex]\begin{gathered} BC=\frac{16sin93^0}{sin29^0} \\ BC=\frac{15.978}{0.485} \\ BC\approx33 \end{gathered}[/tex]Therefore the length of side BC is approximately 33.