Given:
[tex]\frac{(x+q)^2}{100}+\frac{(y-50)^2}{30}=1[/tex]
And
[tex]q=-10[/tex]
Required:
To find the parent function.
Explanation:
The parent function is
[tex]\frac{x^2}{100}+\frac{y^2}{30}=1[/tex]
The transformed function is vertical translation of 50 units upward, and horizontal translation of 10 units right to the parent function.
Final Answer:
The parent function is
[tex]\frac{x^2}{100}+\frac{y^2}{30}=1[/tex]
