Given:
The coordinates,
[tex](\frac{1}{2},\frac{\sqrt[]{3}}{2})[/tex]
The angle is 60 degrees.
The hypotenuse side is 1.
To find:
[tex]\sec 60^{\circ}[/tex]
From the coordinates,
The horizontal side (adjacent side) is,
[tex]\frac{1}{2}[/tex]
The vertical side (opposite side) is,
[tex]\frac{\sqrt[]{3}}{2}[/tex]
Using the trigonometric ratio,
[tex]\begin{gathered} \sec \theta=\frac{\text{hyp}}{\text{adj}} \\ \sec 60^{\circ}=\frac{1}{\frac{1}{2}} \\ =2 \end{gathered}[/tex]
Therefore, the answer is 2.
