Given:-
A graph with an line.
To find:-
The inverse of the given line.
The equation of line is,
[tex]y=mx+c[/tex]Formula for m is,
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So we take two points from the given line. They are (0,1) and (5,2).
Substituting the value we get,
[tex]\begin{gathered} m=\frac{2-1}{5-0} \\ m=\frac{1}{5} \end{gathered}[/tex]So the value of c is,
[tex]\begin{gathered} 1=\frac{1}{5}(0)+c \\ c=1 \end{gathered}[/tex]So the equation is,
[tex]y=\frac{1}{5}x+1[/tex]So the inverse of this line is,
[tex]x=5y-5[/tex]Now we plot the graph of this line and the graph is,
This is the required inverse graph.