we have the quadratic equation
w (x) =2x^2+10x+13
Solve the equation using the formula
so
a=2
b=10
c=13
substitute
[tex]w=\frac{-10\pm\sqrt[]{10^2-4(2)(13)}}{2(2)}[/tex][tex]w=\frac{-10\pm\sqrt[]{-4}}{4}[/tex][tex]\begin{gathered} w=\frac{-10\pm2i}{4} \\ w=-2.5\pm0.50i \end{gathered}[/tex]The given equation don't have real zeros
The solutions are complex numbers