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Question HelpChallenge The price of Stock A at 9 Am was $14.57. Since then, the price has been increasing at therate of $0.12 each hour. At noon the price of Stock B was $15.07. It begins to decrease at the rate of$0.11 each hour. If the two rates continue, in how many hours will the prices of the two stocks be thesame?



Answer :

Let t represent the number of hours it will take the prices of the two stocks to be the same.

The initial price of stock A was $14.57. Given that the price has been increasing at the rate of $0.12 each hour, it means that after t hours, the amount of increase would be

0.12 * t = 0.12t

The final price of stock A after t hours would be

14.57 + 0.12t

The initial price of stock B was $15.07 Given that the price has been decreasing at the rate of $0.11 each hour, it means that after t hours, the amount of decrease would be

0.11 * t = 0.11t

The final price of stock B after t hours would be

15.07 - 0.11t

For the prices to be the same, it means that

14.57 + 0.12t = 15.07 - 0.11t

0.12t + 0.11t = 15.07 - 14.57

0.23t = 0.5

t = 0.5/0.23

t = 2.17

It will take over 2 hours for the prices to be the same.

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