The function f(x) = 3x^2 + 4 is given. To solve for
[g of f] (x), you now have;
[tex]\begin{gathered} \lbrack\text{g of x\rbrack(x);} \\ g(x)=\frac{1}{(x^2-x)} \\ \lbrack g\text{ of x\rbrack(x)=}\frac{1}{(3x^2+4)^2-(3x^2+4)} \\ =\frac{1}{(9x^4+12x^2+12x^2+16)-3x^2+4} \\ =\frac{1}{9x^4+21x^2+20} \end{gathered}[/tex]