Given the following sequence:
[tex]\lbrace6,9,12,15,18,....\rbrace[/tex]It will be an arithmetic sequence because there is a common difference between the terms is constant
d = 9 - 6 = 12 - 9 = 15 - 12 = 18 - 15 = 3
d = 3
The formula of the general term will be as follows:
[tex]a_n=a_1+d(n-1)[/tex]substitute a1 = 6 and d = 3
So, the answer will be:
[tex]a_n=6+3(n-1)[/tex]