6. Everclear grain alcohol is 190-proof (i.e., 95% ethanol by volume), which is near the practical limitfor distillation purity due to chemistry limitations. The density of pure ethanol is 0.789.(a) Determine the percent (by mass) of ethanol in Everclear (in grams). (b) Determine what volumeof Everclear will change its temperature by 11.5°C when 623.0 J of heat is added to it? Hint: thedensity value is used to interconvert between mass and volume.

6 Everclear grain alcohol is 190proof ie 95 ethanol by volume which is near the practical limitfor distillation purity due to chemistry limitations The density class=


Answer :

ANSWER

The mass of ethanol is 74.55 grams

STEP-BY-STEP EXPLANATION:

The % by volume of ethanol is 95%

The density of ethanol is 0.789

Let the mass of ethanol be m

To find the mass of ethanol, we will need to apply the density formula

[tex]\text{ Density = }\frac{mass}{\text{volume}}[/tex]

The next step is to find the volume of the ethanol in the alcohol by using the below formula

[tex]\begin{gathered} \text{ \% by volume = }\frac{volume\text{ of solute}}{\text{volume of solution}} \\ \end{gathered}[/tex]

Assuming 100mL of water was used

% by volume is 95%

Hence, we can calculate the volume of ethanol by using the above formula

[tex]\begin{gathered} 0.95\text{ = }\frac{volume\text{ of ethanol}}{100} \\ \text{Volume of ethanol = 0.95 }\times\text{ 100} \\ \text{Volume of ethanol = 95 mL} \end{gathered}[/tex]

The next step is to find the mass of the ethanol

[tex]\begin{gathered} \text{Density = }\frac{mass}{\text{volume}} \\ \text{mass = density x volume} \\ \text{mass = 0.789 }\times95 \\ \text{mass = 74.955 grams} \end{gathered}[/tex]

Therefore, the mass of ethanol is 74.55 grams