73.02 grams
Given the following parameter
Atom of hydrogen = 9.42x10^24 atoms
From the given compound, for every 9 moles of hydrogen, there are 3 moles of nitrogen, hence the atoms of nitrogen present in the compound will be:
[tex]\begin{gathered} atoms\text{ of nitrogen}=\frac{3}{9}\times9.42\times10^{24} \\ atoms\text{ of nitrogen}=3.14\times10^{24}atoms \end{gathered}[/tex]Convert atoms to moles
[tex]\begin{gathered} moles\text{ of nitrogen}=\frac{3.14\times10^{24}}{6.02\times10^{23}} \\ moles\text{ of nitrogen}=0.521\times10 \\ moles\text{ of nitrogen}=5.21moles \end{gathered}[/tex]Convert moles of nitrogen to mass
[tex]\begin{gathered} mass\text{ of nitrogen}=mole\times molar\text{ mass} \\ mass\text{ of nitrogen}=5.21moles\times\frac{14g}{mol} \\ mass\text{ of nitrogen}=73.02grams \end{gathered}[/tex]Hence the mass of nitrogen contained in the sample is 73.02 grams