A spinner is spun 20 times. The spinner has 4 colored sections of equal size. The table shows the results red= 4black= 6 blue= 3green=7 What is the experimental probably of not stopping on the color blue? Leave your answer as a reduced fraction (numerator/denominaton,



Answer :

Given:

Number of times the spinner is spun, n = 20 times

Number of colored sections = 4

We have the table:

Red = 4

Black = 6

Blue = 3

Green = 7

Let's find the probability the spinner does not stop on the blue color.

To find the probability, apply the formula:

[tex]P(\text{not blue) = 1 - P(blue)}[/tex]

To find P(blue), we have:

[tex]P(\text{blue)}=\frac{\text{Number of blue}}{\text{Total number of times the spinner is spun}}=\frac{3}{20}[/tex]

Thus, we have:

[tex]\begin{gathered} P(\text{not blue)= 1 - }\frac{3}{20} \\ \\ =\text{ }\frac{1}{1}-\frac{3}{20} \\ \\ =\frac{20-3}{20} \\ \\ =\frac{17}{20} \end{gathered}[/tex]

Therefore, the experimemtal probability of not stopping on the color blue is 17/20

ANSWER:

[tex]\frac{17}{20}[/tex]