Answer:
82.95g of oxygen gas react with 27.0g of acetylene.
Explanation:
1st) It is necessary to balance the chemical reaction:
[tex]2C_2H_2+5O_2\rightarrow4CO_2+2H_2O[/tex]With the chemical reaction we know that 2 moles of C2H2 react with 5 moles of O2 to produce 4 moles of CO2 and 2 moles of water.
2nd) With the molar mass of acetylene and oxygen we can convert the moles to grams:
- Acetylene molar mass (C2H2): 26.04g/mol
- Oxygen molar mass (O2): 32g/mol
- Conversion of C2H2 moles to grams:
[tex]2moles*\frac{26.04g}{1mol}=52.08g[/tex]- Conversion of O2 moles to grams:
[tex]5moles*\frac{32g}{1mol}=160g[/tex]Now we know that 52.08g of acetylene react with 160g of oxygen gas.
3rd) Calculate the grams of oxygen that react with 27.0g of acetylene, using a mathematical rule of three:
[tex]\begin{gathered} 52.08g\text{ C}_2\text{ H}_2-160g\text{ O}_2 \\ 27.0g\text{ C}_2\text{ H}_2-x=\frac{27.0g\text{ C}_2\text{ H}_2*160g\text{ O}_2}{52.08g\text{ C}_2\text{ H}_2} \\ x=82.95g\text{ O}_2 \\ \end{gathered}[/tex]So, 82.95g of oxygen gas react with 27.0g of acetylene.