Answer :
In this case, we have a gas at constant pressure that varies its volume and temperature. The law that we can apply in this case is Charles's law, which relates temperature and volume while maintaining a constant pressure. Charles's law is described as:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]Where,
V1 is the initial volume in liters, V1=365mL=0.365L
T1 is the initial temperature in Kelvin, T1=0°C=273.15K
T2 is the final volume in Kelvin, T2=25°C=298.15K
V2 is the final volume in Liters, V2=?
Now, we clear V2 and we replace the known data:
[tex]\begin{gathered} V_2=\frac{V_1}{T_1}\times T_2 \\ V_2=\frac{0.365L}{273.15K}\times298.15K=0.398L\times\frac{1000mL}{1L} \\ V_2=398mL \end{gathered}[/tex]Answer: If the temperature rises to 25 degree Celsius the volume would be 398mL
