We know that the product of the concentrations of OH and H ions represents a constant.
[tex]\lbrack H^+\rbrack\lbrack OH^-\rbrack=1\times10^{-14}_{}[/tex]Then, we solve for OH concentration.
[tex]\lbrack OH^-\rbrack=\frac{1\times10^{-14}}{0.001}=1\times10^{-11}M[/tex]Therefore, the concentration of hydroxide is C. 1x10^-11 M.