The area of the circle is
[tex]A=\pi(r)^2[/tex]
The perimeter of the circle is (its circumference)
[tex]P=2\pi(r)[/tex]
r is the radius of the circle
Since r = 3 ft, then
[tex]\begin{gathered} A=\pi(3)^2=9\pi ft^2 \\ P=2\pi(3)=6\pi\text{ ft} \end{gathered}[/tex]
The area of the triangle is
[tex]A=\frac{1}{2}bh[/tex]
b is the base
h is the height
Since the base is 5 ft, and the height is 5 ft, then
b = 5
h = 5
[tex]A=\frac{1}{2}(5)(5)=12.5ft^2[/tex]
Since the 3 sides of the triangle are equal, then its perimeter is the sum of the 3 sides
[tex]P=5+5+5=15ft[/tex]
The area of the square is
[tex]\begin{gathered} A=s\times s \\ P=s\times4 \end{gathered}[/tex]
Since the side of the square is 5 ft
[tex]\begin{gathered} A=5\times5=25ft^2 \\ P=5\times4=20ft \end{gathered}[/tex]
