A manufacturer knows that their items have a normally distributed lifespan, with a mean of 6.9 years, and standard deviation of 1.6 years. If you randomly purchase one item, what is the probability it will last longer than 10 years ?



Answer :

ANSWER

0.9738 or 97.38%

EXPLANATION

Given:

[tex]\begin{gathered} mean(\mu)=6.9 \\ Standard\text{ }Deviation(\sigma)=1.6 \end{gathered}[/tex]

Desired Outcome:

Probability that it will last 10 years

z-score for the sample:

[tex]\begin{gathered} z-score=\frac{X-\mu}{\sigma} \\ z-score=\frac{10-6.9}{1.6} \\ z-score=1.9376 \end{gathered}[/tex]

p-value

For the z-score of 1.9376, the p-value is 0.9738 or 97.38%

Hence, the probability that it will last longer than 10 years if you randonly purchase one item is 97.38%