Juan scored 15 points more than on this test than his previous test. If the average of the two tests is at least 92 and both scores are integers what are the least scores he could have had on the two tests.



Answer :

The least scores Juan could have had in the two tests are 85 and 100

How to determine the possible scores on the tests?

Let the test scores be x and y

Where x is the current test and y is the previous test

Using the interpretation of the parameters in the question, we have the following:

x = y + 15 --- the relationship between the test scores

The average test scores can be represented as

1/2(x + y) ≥ 92

Substitute x = y + 15 in 1/2(x + y) ≥ 92

1/2(y + 15 + y) ≥ 92

Evaluate the like terms

1/2(2y + 15) ≥ 92

So, we have

2y + 15 ≥ 184

This gives

2y ≥ 169

Divide by 2

y ≥ 84.5

From the question both numbers are integers

So, we can assume that y = 85

Substitute y = 85 in x = y + 15

x = 85 + 15

Evaluate

x = 100

Hence, the possible test scores are 85 and 100


Read more about inequalities at

https://brainly.com/question/25275758

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