In this question, we have a situation in which we have to use the Calorimetry formula, which is how much heat was released or absorbed (in Joules), after we had a change in temperature of a compound. The formula for this Calorimetry question is:
Q = mcΔT
Where:
Q = is energy as Heat
m = mass in grams, 323.7 mL is 323.7 grams (1 mL = 1 gram of water)
c = is the specific heat capacity, 4.184 J/g°C
ΔT = the change in temperature, calculated as Final Temperature - Initial T
26.15 - 22.55 = 3.6°C
Now we add these values into the formula:
Q = 323.7g * 4.184 * 3.6
Q = 4.876 Joules or 4.9 kJ was the heat gained by water