Solution
Given
[tex]\begin{gathered} m<3=45^0 \\ m<1=50^0 \\ m<6=135^0 \end{gathered}[/tex][tex]\begin{gathered} m<6\text{ = m<1 + m<2 + m<3 \lparen corresponding angles are equal\rparen} \\ 135=50+m<2+45 \\ 135=95+m<2 \\ m<2=135-95 \\ m<2=40^0 \end{gathered}[/tex][tex]\begin{gathered} m
