[tex]\begin{gathered} \text{Volume of a pyramid =}\frac{1}{3}\text{ x base area x height} \\ \text{Base area = L}^2 \\ =\text{ 4cm x 4cm } \\ =16\operatorname{cm} \\ \text{heigth = 3cm} \\ \text{volume = }\frac{1}{3}\text{ x 16 x 3} \\ =16^{^{}}cm^3 \end{gathered}[/tex]
16 cm^3 of sand is needed to fill the weight
