To answer this question we will use the following diagram as a reference:
Therefore the surface area of the given solid is:
[tex]\begin{gathered} SA=2(4cm\times1cm)+2(1cm\operatorname{\times}1cm)+2(1cm\operatorname{\times}4cm)+2(4cm\operatorname{\times}1cm)+1cm\operatorname{\times}4cm \\ +3cm\operatorname{\times}4cm+4cm\operatorname{\times}4cm. \end{gathered}[/tex]
Simplifying the above result we get:
[tex]\begin{gathered} SA=8cm^2+2cm^2+8cm^2+8cm^2+4cm^2+12cm^2+16cm^2 \\ =58cm^2 \end{gathered}[/tex]
Answer: Option B.
