First, we compute the equation of the line that passes through (5,-5) and has slope -2/3 using the slope-point formula:
[tex]y-(-5)=-\frac{2}{3}(x-5)\text{.}[/tex]
Solving for y we get:
[tex]\begin{gathered} y=-\frac{2}{3}x+\frac{10}{3}-5, \\ y=-\frac{2}{3}x-\frac{5}{3}\text{.} \end{gathered}[/tex]
Therefore, (0,-5/3) is the y-intercept of the line.
Answer:
